Question

in piramida patrulatera regulata VABCD triunghiul VAC echilateral cu AC=10radical din 2.Calculati:a)muchia bazei b)inaltimea piramidei c)apotema piramidei

Answer 1

a) mb=?
  AC diag patrat 
  diag patrat= 10√2
  l√2=10√2
  l=10√2/√2
  l=10cm
b)h piramida=?
 VAC echilat
VA=AC=VC=10√2cm 
=>h=l√3/2=10√2*√3/2=5√6cm
c) ap=VM=?
MC=BC/2=10/2=5cm
VC=10√2                          
=> In triunghiul VOM dr
              m(<0)=90 grade}=> T.P.=>VC^2=VM^2+MC^2= (10√2)^2=VM^2+5^2= 100*2=VM^2+25=VM^2=200-25=VM^2=175/√ => VM=5√7cm  
ap=5√7cm
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