Question

In procesul de nitrare a 390 kg de benzen s-au obtinut 430,5 kg de mononitrobenzen. Determinati randamentul reactiei.

Answer 1

C6H6 + HONO2  = C6H5-NO2 + H2O
teoretic n NB = nB = 390/78 = 5kmoli  m = 5 x 123 = 615kg
m practic = 430,5Kg
η = 430,5 x100/615 = 70%

Answer 2

C6H6 + HNO3 = C6H5-NO2 + H2O
M C6H6 = 12*6+6*1 = 78
M C6H5NO2 = 6*12+5*1+14+2*16 = 123
78 g benzen.....123 g nitrobenzen
x...........................430,5 kg nitrobenzen
x = 273 kg C6H6
randament = m practică/ m teoretică * 100 = 273/390 * 100 = 70%