Question

In reactiile de mai jos, numite reactii de disproportionare, aceeasi specie chimica este si agent oxidant si agent reducator. Identificati semireactia de oxidare si semireactia de reducere si egalati ecuatiile urmatoarelor reactii redox:

Answer 1

a) 3K⁺¹Cl⁺¹O⁻² ⇒ K⁺¹Cl⁺⁵O₃⁻² + 2K⁺¹Cl⁻¹

Cl⁺¹ +4e⁻⇒ Cl⁺⁵  ||2||1 se reduce (agent oxidant)
Cl⁺¹ -2e⁻ ⇒ Cl⁻¹  ||4||2 se oxideaza (agent reducator)

b) 2Na⁺¹O⁻²H⁺¹ + Cl₂⁰ ⇒ Na⁺¹Cl⁻¹ + Na⁺¹Cl⁺¹O⁻² + H2⁺¹O⁻²

Cl₂⁰ -2e⁻→ 2Cl⁻¹ ||2||1 se oxideaza (ag.red)
Cl₂⁰ +2→ 2Cl⁺¹   ||2||1 se reduce (ag.ox)

c) Cl₂⁰ + H₂⁺¹O⁻² ⇄ H⁺¹Cl⁻¹ + H⁺¹O⁻²Cl⁺¹

Cl₂⁰ -2e⁻→ 2Cl⁻¹ se oxideaza (ag.red) ||2||1

Cl₂⁰ +2e⁻→ 2Cl⁺¹ se reuce (ag.ox) ||2||1

d) 2N⁺⁴O₂⁻² + 2Na⁺¹O⁻²H⁺¹ → Na⁺¹N⁺³O₂⁻² + Na⁺¹N⁺⁵O₃⁻² + H₂⁺¹O⁻²

N⁺⁴ +1e⁻→ N⁺³ se reduce (agent oxidant)         |1

N⁺⁴ -1e⁻→ N⁺⁵ se oxideaza (agent reducator)   |1

e) P₄⁰ + 3K⁺¹O⁻²H⁺¹ + 3H2⁺¹O⁻² ⇒ P⁻³H₃⁺¹ + 3K⁺¹H₂⁺¹P⁺¹O₂⁻²

P₄⁰ -12e⁻→ 4P⁻³ se oxideaza (agent reducator) ||4||1

P₄⁰ +4e⁻→ 4P⁺¹ se reduce (agent oxidant) ||12||3

i'm not sure :)