Question

in reperul cartezian xoy se considera punctele A(3,1) , B(-1,4) si C(3,7).calculati perimetrul triunghiului abc. Ajutima va rog din suflet! Dau coroana <3

Answer 1

P = AB + BC + AC

$ab = \ \: \sqrt{(x2 - x1) ^{2} + {(y2 - y1)}^{2} }$

$ab = \sqrt{{( - 1 - 3)^{2} } + (4 - 1) ^{2} }$

$ab = \sqrt{16 + 9}$

$ab = \sqrt{25}$

AB = 5

$bc = \sqrt{(3 - - 1)^{2} + {(7 - 4)}^{2} }$

$bc = \sqrt{16 + 9}$

$bc = \sqrt{25}$

BC = 5

$ac = \sqrt{(3 - 3)^{2} + {(7 - 1)}^{2} }$

$ac = \sqrt{0 + {6}^{2} }$

$ac = \sqrt{36}$

AC = 6

P = AB + BC + AC

P = 5 + 5 + 6

P = 16