Question

In reperul cartezian xoy se considera punctele A(3,5) si B (7,5) Determinati coordonatele mijlocului segmentului AB

Answer 1

$A(3;5) \\ \\ B(7;5) \\ \\ \text{Fie M mij [AB]} \\ \\ X_M = \dfrac {X_A+X_B}{2} \\ \\ X_M = \dfrac {3+7}{2} \\ \\ X_M = \dfrac {10}{2} \\ \\ X_M = 5 \\ \\ \\ \\ Y_M = \dfrac {Y_A+Y_B}{2} \\ \\ Y_M = \dfrac {5+5}{2} \\ \\ Y_M = \dfrac {10}{2} \\ \\ Y_M = 5 \\ \\ \\ \rightarrow \boxed { M(5;5)}$

Answer 2

A(3,5) B(7,5)
A(xA,yA),B(xB-yB)
AB=√(xB-xA)²+(yB-yA)²=√(7-3)²+(5-5)²
=√4²+0=√16+0=√16=4
M(xA+xB/2,yA+yB/2)
M(3+7/2,5+5/2)
M(10/2,10/2)
M(5,5)