Question

In reperul cartezian xOy se considera punctele A(-4,1), B(2,3) si dreapta d: y=2x+a. Determinati nr real a , stiind ca mijlocul segmentului AB apartine d.
URGEENT!!!!​

Answer 1

Formula: XM= XA +XB / 2

YM= YA+YB / 2

XM= -4 +2 / 2 = -2/2= -1

YM= 1+2/ 2 = 4/2 = 2

2=2×(-1) +a

2=-2+a

a-2-2

a=2+2

a=4