Question

In reperul cartezian xOy se considera  punctele P(1,3) si R(3,3).Determinati coordonatele punctului Q,stiind ca R este mijlocul segmentului PQ.

Answer 1

$Q( x_{Q}, y_{Q} ) \\ \\ x_{Q}= \frac{ x_{P}+ x_{R} }{2} \\ \\ x_{Q}= \frac{ 1+3 }{2} \\ \\ x_{Q}=2 \\ \\y_{Q}= \frac{ y_{P}+ y_{R} }{2} \\ \\ y_{Q}= \frac{ 3+ 3 }{2} \\ \\ y_{Q}=3 \\ \\ Q(2,3)$

Answer 2

Xr = (Xp + Xq) / 2
3 = (1 + Xq) / 2
1 + Xq = 3 * 2
Xq = 6 - 1
Xq = 5

Yr = (Yp + Yq) / 2
3 = (3 + Yq) / 2
3 + Yq = 3 * 2
Yq = 6 - 3 
Yq = 3

⇒Q (5 , 3)