Question

In rombul ABCD, BD=24radical din 2,si m(unghiuluiADC)=120 de grade.CAlculati lungimea diagonaleii AC si Perimtrul Rombuluii..
STITII VA ROG AJUTATI MA :) :)

Answer 1

m<D=m<B=120
m<D1=m<D2=m<D/2=120/2=60 grade
m<B1=m<B2=m<B/2=120/2=60 grade
ΔABD m<D1=m<B1=60⇒m<A=180-60-60=60⇒ΔABD-echilateral
⇒BD=AB=AD=DC=BC=24√2
inΔ ABD AO=h⇒AO=l√3/2=24√2*√3/2=12√6
inΔBCD OC=h⇒OC=l√3/2=24√2*√3/2=12√6 din amandoua rezulta ca ⇒AC=2*12√6=24√6
P=4l=4*24√2=96√2