Question

In trapezul ABCD, AB||CD, AB>CD, [AD] = [BC], m(<DAB) = 80° si m(<CDB) = 35°.Atunci m(<CBD) este egala cu:
A.30°
B.35°
C.40°
D.45°

Vreau rezolvare. Dau coroana+toate punctele mele

Answer 1

AD =BC  =><) A=B =80 grade ;  =>    <) ADC =180-80 =100 gr

<) CDB=35gr  ; CD//AB si <) CDB =35 gr  => <)CBD =80-35 =45 gr.

( BD = cecanta)