Question

in trapezul ABCD , AB paralel cu DC , AB>DC , se prelungesc laturile naparalele AD si BC . Fie {M}=ADintersectiaBC .Calculati lungimile segmentelor .
a) CM , daca AD=18 cm, BC=6cm , DM=15cm
b)MD, daca AD=3,6cm si BC supra MC=3 supra 4:1,25.
c)BC, daca BC-CM=7,2dm si AD supra DM=17 supra 5 .

VA ROG AJUTATI-MAAAA !!! va rog muuult !!! :(

Answer 1

a) AB||CD⇒ T.Th  MD/AD=MC/BC⇒ 15/18=MC/6⇒MC= 15*6/18= 5 cm

b) AB||CD⇒ T. Th AD/MD= BC/MC=3/4:125/100=3/4*100/125=3/4*4/5=3/5
   3,6/MD=3/5⇒ MD= 3,6*5/3=1,2*5=6 cm

c) AD/MD=BC/CM= 17/5⇒ BC=17CM/5=34CM/10=3,4CM
   3,4CM-CM=7,2⇒ 2,4 CM= 7,2⇒ CM=7,2/2,4⇒ CM=3 cm