Question

In trapezul ABCD cu AB||DC,avem CD=6cm,AB=18cm,AD=8cm si BC=10cm.Daca AD intersectat cu BC={M},aflati lungimea segmentelor MD,MA,MC,MB.

Answer 1

MD/MA =DC/AB
MD/MD+DA =6/18
MD/MD+8 =6/18
18MD =(6MD+8)
18MD=6MD+48
18MD-6ND=48
12MD =48
MD =4 cm
MA =MD+DA =4+8 =12 cm

MD/MA =MC/MB
4/12 =MC/MC+10
12MC =4(MC+10)
12MC =4MC+40
12MC -4MC =40
8MC =40
MC =5 cm
MB =MC+BC =5+10=15 cm

Answer 2

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