Question

In trapezul dreptunghic ABCD, cu AB || CD, m( <A ) = 90 grade , AB = 16 CM , CD=8cm si AD= 6cm. Calculati
a) lungimea segmentului [BC]
b) Aria trapezului
c) Perimetrul triunghiului MDC, daca AD intersectat cu BC = {M}

REPEDE / FAST / GO

Answer 1

a) CE =inaltimea
CE=AD=6
EB=AB-DC=16-8=8
CB²=EC²+EB²=6²+8²=36+64=100
CB=√100=10
b)A=(B+b)*inalt/2=(16+8)*6/2=52*6/2=156
c) MD/DA=DC=AB
MD/6=8/16
MD=6*8/16=48/16=3
AM=AD+MD=6+3=9
MC/CB=DC/AB
MC/10=8/16
MC=10*8/10=8
MB=MC+CB=8+10=18
PerimetrulMDC=MD+DC+MC=3+8+8=19

Answer 2

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