Question

in triunfhiul ABC Se cunosc m(A)=90 , AB=6cm, AC 3cm . Qflati sin C

Answer 1

Δ ABC, m<A=90, AB=6, BC=3⇒Th Pitagora BC²=AB²+AC²
BC²=36+9=45
BC=3√5
sinC=$\frac{AB}{BC} = \frac{6}{3 \sqrt{5} } = \frac{2}{ \sqrt{5} } = \frac{2 \sqrt{5} }{5}$