Question

In triunghiul ABC AC=4, BC=6 m(B^)=30 grade. Calculati sin A.

Answer 1

Salut,

Teorema sinusurilor:

$\dfrac{AC}{sinB}=\dfrac{BC}{sinA},\ deci\ sinA=\dfrac{BC\cdot sinB}{AC}=\dfrac{6\cdot \dfrac{1}2}{4}=\dfrac{3}4.$

Simplu, nu ?

Green eyes.