Question

in triunghiul ABC,AD este h,D∈BC,AB=√5,AC=3√3 si BC=4√2cm.Calculati AD,BD,DC.

Answer 1

ΔABC
AB=√5  ⇒AB²=5
AC=3√3 ⇒AC²=27
BC=4√2 ⇒BC²=32
32=27+5
BC²=AC²+AB²                    din toate⇒ mas<A=90  ΔABC-dreptunghic

AD=AC*AB/BC= 3√3*√5/4√2= 3√15/4√2= 3√30/4*2=   3√30/8
AB²=BD*BC
5=BD*4√2
BD=5/4√2 =  5√2/4*2=   5√2/8

AC²=DC*BC
27=DC*4√2
DC=27/4√2=  27√2/4*2=  27√2/8