Question

In triunghiul Abc avem A=90°, cosB=3/5. calculati sin C.

Answer 1

$\cos(b) = \frac{3}{5} = \frac{ab}{bc} \\ \sin(c) = \frac{ab}{bc} = \frac{3}{5}$

Answer 2

Sin c = AB/CB
COS B =AB/CB
COD B =3/5
=> Sin C = 3/5