Question

in triunghiul abc i centrul cercului inscris,iar m CIA=110.Determinati m Abc

Answer 1

Răspuns:

Explicație pas cu pas:

Answer 2

$\it \hat In\ \Delta AIC \Rightarrow 180^o-\Big(\dfrac{\hat A}{2}+\dfrac{\hat C}{2}\Big)=110^o \Rightarrow \dfrac{\hat A+\hat C}{2}=70^o \Rightarrow \hat A+\hat C=140^o\\ \\ \\ \hat In\ \Delta ABC \Rightarrow\hat B= 180^o-(\hat A+\hat C)=180^o-140^o=40^o$