Question

in triunghiul ABC m(A)=90 de grade . AB=9cm si sin(C)=3pe 5
.Atunci BC egal cu ?

Answer 1

sin C=AB/BC=3/5
9/BC=3/5
BC=5*9/3=15 cm

Answer 2

$Rezolvare:sin(C)= \frac{AB}{BC}\to \frac{3}{5} \\ \to sin(C)=\frac{9}{BC}= \frac{3}{5} \\ BC=5* \frac{9}{3}\to \frac{45}{3} \to15cm$