Question

in triunghiul abc m(a) = 90° ab =6 cm bc=10 cm Aflati ac si ad unde ad perpendi cu bc d apartine lui bc

Answer 1

AC^2=BC^2-AB^2
AC^2 =10^2-6^2
AC^2 =100-36 =64
AC =8 cm

h =AB*AC/BC  =6*8/10 =48/10 =4.8 cm