Question

in triunghiul ABC , m(unghiului B)= 90°,avem BC =5 cm si sin C =√
$\frac{ \sqrt{3} }{2}$
. calculati cosC, AC, AB,tgC,ctgC

Answer 1

sin(C) =$\frac{ \sqrt{3} }{2}$
m(C) = 60°
cos(C) = 1 ÷ 2
AC = cos(C)^(-1)×BC = 2 × BC = 10 cm
tg(C) = $\sqrt{3}$
ctg(C) = $\frac{ \sqrt{3} }{3}$