Question

In triunghiul ABC masura unghiului B=90de grade
Stiind ca BC=5cm si sinC=radical din 3 supra 1 calculati:cosC Ac AB tgC ctgC.Dau coroana

Answer 1

sin C =√3
sin C= AB/BC
√3/1=AB/5 =>AB=5√3 cm
In ∆ ABC dr =>TP
BC² +AB²=AC²
5²+(5√3)²=AC²
AC² =25+75
AC²=100.
AC=√100
AC=10 cm
cos C= AC/BC
cos C= 10/5
Cos C=2
tg =AB/AC
tg C= 5√3/10
tg C= √3/2
ctg C=AC/AB
ctg C = 10/5√3
ctg C =2/√3