Question

In triunghiul abc se cunosc m A=90 Ac=6m ab=6/2m aflati si B cos B si tg C

Answer 1

AB=6/2 m=3m
BC²=AC²+AB²=6²+3²=36m²+9m²=45m²  =>
BC=√45m²=3√5 m   ---ipotenuza triunghiului dreptunghic
sin=cat.opusa / ipotenuza
sinB=AC/BC=6m/3√5m= 2/√5=2√5 / 5
cos=cat.alaturata / ipotenuza
cosB=3/3√5=1/√5=√5 /5
tg=sin / cos
sinC=cosB=√5 /5
cos C=sin B=2√5 /5
tg(C)=√5 / 2√5=1/2