Question

in triunghiul drept ABC avem masura unghiului A de 90° AB=6cm si BC=10cm. Calculati sinB+sinC

Answer 1

Prin teorema lui pitagora avem:
AC la a doua=BC la a doua-AB la a doua
AC la a doua= 100-36=64=8 la a doua
=> AC=8.

sin B= AC/BC= 8/10=4/5.
sinC=AB/BC=6/10=3/5.

sinB+sinC= 4/5+3/5=7/5.