Question

in triunghiul dreptunghic abc (a 1dr) AB =12,BC=20,AD PERPENDICULAR PE BC CALCULATI INALTIMEA SI perimetrul

Answer 1

AB^2+AC^2=BC^2
AC^2 - 20^2-12^2=256  => AC=16 ;

AD=(12*16)/20 = 9;6 ;
P = 12+16+20 = 48 ;