Question

in triunghiul dreptunghic abc a = 90 , AD perpendicular pe BC ,D apartine BC , se da AB = 65 si BD supra BC = 25 supra 169. Calculati BD , CD , BC si AC

Answer 1

AB=\sqrt{BDoriAC} [/tex]<=> AB=$\sqrt{169ori25}$=[tex] \sqrt{4225}=65=> BD=25; BC=169. CD=169-25=144. AC^2=BC^2-AB^2=28561-4225=24336<=> AC=156