Question

In triunghiul dreptunghic ABC (m( unghiului A)=90 grade),avem sin B < sin C.Demonstrati ca tg B < 1 ​ AJUTOR!!!

Answer 1

$\it sinB < sinC \Rightarrow \dfrac{AC}{BC} < \dfrac{AB}{BC} \Rightarrow AC < AB \Big|_{:AB} \Rightarrow \dfrac{AC}{AB} < 1\ \ \ \ \ (*)\\ \\ \\ tgB=\dfrac{AC}{AB} \stackrel{(*)}{\Longrightarrow}\ tgB < 1$