Question

in triunghiul dreptunghic cu ipotenuza de 20cm si o cateta de 12 cm are perimetrul egal cu....cm

Answer 1

$I = 20 \: cm$

$C_{1} = 12 \: cm$

${I}^{2}={C_{1}}^{2}+{C_{2}}^{2}$

${C_{2}}^{2} = {I}^{2} - {C_{1}}^{2}$

${C_{2}}^{2} = {20}^{2} - {12}^{2}$

${C_{2}}^{2} = 400 - 144$

${C_{2}}^{2} = 256$

$C_{2} = \sqrt{256}$

$C_{2} = 16 \: cm$

$P=I+C_{1}+C_{2}$

$P=20 + 12 + 16$

$P = 48 \: cm$