Question

In triunghiul echilateral avem
a3=3 radical 6 cm
Aflati:l3
h3
R3
A3

Answer 1

A3= l²√3/ 4
36√3= l²√3 / 4
36√3 ×4= l²√3
l3= 12
P= 3×l =36
l3= R√3 ⇒R= 12/ √3= 4√3

Answer 2

$R_3=2\cdot a_3 =2\cdot3\sqrt6=6\sqrt6\\ \\ l_3=R\sqrt3\\ \\ \mathcal{A}_{\triangle}=\dfrac{\ell^2\sqrt3}{4}$

$\it h=a_3+R$