Question

In triunghiul isoscel ABC, AB = AC = 30 cm si lungimea bazei BC = 36 cm. Calculati lungimile inaltimilor triunghiului ABC

Answer 1

AD⊥BC ; BE⊥AC si CF⊥AB
ΔABC isoscel⇒ AD-h⇒ AD-mediana⇒ D-mijlocul BC⇒BD=DC=18 cm
in ⇒ADB dreptunghic⇒ TP⇒ AB²=AD²+DC²⇒ 900 = AD²+324
AD²= 900-324= 576⇒ AD=24 cm

A ABC = AD*BC :2 = BE*AC:2 = CF*AB:2
24*36 = BE*30 = CF*30

BE=CF=24*36:30 =28,8 cm