Question

In triunghiul TAE din figura alaturata,HS||AE si SL||TA.Daca TH=3,TS=5,SE=8,LE=6, calculati perimetrul paralelogramului HALS.

Answer 1

HALS- paralelogram⇒ HA=SL si HS=AL
HS || AE⇒ T Th. TH/HA=TS/SE⇒ 3/HA=5/8⇒ HA=8*3/5=24/5=4,8 cm⇒ SL=4,8cm
SL || TA⇒ T. Th. SE/ST=LE/LA⇒ 8/5=6/LA⇒ LA=6*5/8=30/8= 3,75 cm⇒ HS=3,75 cm
P HALS= HA+AL+LS+SH = 4,8 * 2 + 3,75 * 2= 9,6 + 7,5 = 17,1 cm