Question

In urma analizei cu oxigen a 3,7g de substanta organica s-au obtinut 896mL CO, 3,584L CO2 si 4,5g H2O. Stiind ca substanta contine un atom de oxigen. Formula ei moleculara este?
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Answer 1

m/M=V/Vm=>m=M*V/Vm=28*896/22,4=1120mg=1,12g CO

28g CO.................12g C
1,12g CO...............x=0,48g C

m/M=V/Vm=>m=44*3,584/22,4=7,04g CO2

44g CO2..................12g C
7,04g CO2................x=1,92g C

18g H2O........................2g H2
4,5g H2O.......................x=0,5g H2

m O =3,7-0,48-1,92-0,5=0,8g O

m C total = 1,92+0,48=2,4g C

n=m/M=2,4/12=0,2 moli C => 4 atomi C

n=m/M=0,5/2=0,25 moli H => 10 atomi H

n=m/M=0,8/16=0,05 moli O => 1 atom O

F.M => C4H10O