Question

in urma reactiei a 180 g carbid cu apa s-au obtinut 33,6bacetilena. cat este puritatea

Answer 1

Calculez nr.moli   acetilena;iau 33,6 litri???????
niu sau n= 33,6l/22,4l/mol= 1,47mol acetilena
Ecuatia reactiei
1mol                   1mol
CaC2  +H2o   = C2H2  +CaO
n=1,47................1,47
calculez masa de carbid pur
m= 1,47molx(40gCa+24gC)/mol=94,08g carbid pur
calculez puritatea: p/100= m,pur/ m,impur;  p/100= 94,08/ 180
calculeaza !!!!!!!!