Question

In urma reactiei NaOH cu H2SO4 rezulta 3 moli NaSO2. Calculeaza:
a)mNaOH de puritate 60% introdusa in reactie;
b) numarul de moli de apa rezultata;
c)masa de solutie H2SO4 de concentratie 49% constanta in reactie;
Cat mai repede va rog!!

Answer 1

2NaOH + H2SO4 -> Na2SO4 + 2H2O

a)

2 moli NaOH...........................1 mol Na2SO4
x moli NaOH...........................3 moli Na2SO4

x=2*3=6 moli NaOH

MNaOH=40g/mol

n=m/M=>m=n*M=6*40=240g pur NaOH

p=mp/mimp*100 => mimp=mp*100/p=240*100/60 = 

b) 1 mol Na2SO4....................2 moli H2O
3 moli Na2SO4........................x= 6 moli H2O

c) MH2SO4=98g/mol

98g H2SO4.......................1 mol Na2SO4
x g H2SO4.........................3 moli Na2SO4

x=3*98=294g H2SO4 (md)

C=md/ms*100=>ms=md*100/C=294*100/49 =