Question

inaltimea triunghiului cu laturile de 6cm,9cm,12cm

Answer 1

$A_{tr.}= \frac{1}{2}* h_{a} \\ A_{tr.}= \sqrt{p(p-a)(p-b)(p-c)}$
$A_{tr.}= \sqrt{ \frac{27}{2}( \frac{27}{2}-6)( \frac{27}{2}-9)( \frac{27}{2}-12) } = \\ = \sqrt{ \frac{27}{2}* \frac{15}{2}* \frac{9}{2}* \frac{3}{2} }= \frac{9}{4} \sqrt{15}$
$\frac{9}{4} \sqrt{15}=3h \\ h= \frac{3}{4} \sqrt{15}$