Question

Indicati denumirea trigliceridei stiind ca acizii componenti sunt saturati,iar prin saponificarea a 21.55 g de triglicerida rezulta 15.3 g de sapun cu
7.516 % Na,respectiv 6.95 g de sapun cu 8.273 %Na

Answer 1

Cel mai simplu
primul sapun: CH3-(CH2)n-COONa
al doilea sapun: CH3-(CH2)m-COONa
Msapun=14n+82 g/mol respectiv 14m+82 g/mol
7,516%=23*100%/(14n+82)
14n+82=23*100/7,516=306 => 14n=224 => n=16 => acidul 1: acidul stearic
14m+82=23*100/8,273=278 => 14m=196 => m=14 => acidul 2: acidul palmitic
avem amestec de palmitat de sodiu si stearat de sodiu
transformam in moli masele de sapunuri
nstearat=15,3/306=0,05moli
npalmitat=6,95/278=0,025moli
stearat:palmitat=0,05:0,025=2:1
=> triglicerida: distearopalmitina