Question

Inmultirea cand unul dintre factori este o suma Calculeaza in doua moduri:5x4(4+3)
6x(5+4)
5x6+5x3
3x6+6x7

Answer 1

Răspuns:

a) 5 x 4(4+3)= 5x 4 x 7= 140

= 5x ( 4x4+4x3)= 5x(16+12)=5x28= 140

b) 6x(5+4) = 6x 9= 54

= 6x5 +6x4=30+24=54

c)5x6+5x3= 30+15= 45

= 5x(6+3)= 5x9= 45

d)3x6+6x7= 18+42= 60

= 6x(3+7) = 6x10 = 60

Sper ca te-am ajutat (⊃ • ʖ̫ • )⊃

Answer 2

Primul mod :

5 × 4 ( 4 + 3 ) =

20 × 7 = 140

6 × ( 5 + 4 ) =

6 × 9 = 54

5 × 6 + 5 × 3 =

30 + 15 = 45

3 × 6 + 6 × 7 =

18 + 42 = 60

Al doilea mod :

5 × 4 ( 4 + 3 ) =

5 × 4 × 4 + 5 × 4 × 3 =

20 × 4 + 20 × 3 =

80 + 60 = 140

6 × ( 5 + 4 ) =

6 × 5 + 6 × 4 =

30 + 24 = 54

5 × 6 + 5 × 3 =

5 × ( 6 + 3 ) =

5 × 9 = 45

3 × 6 + 6 × 7 =

6 × ( 3 + 7 ) =

6 × 10 = 60