Question

Integrala arctg^6 x/1+x^2 dx x apartine lui R

Answer 1

$\int\limits{ \frac{ arctg^{6}x }{1+ x^{2} } } \, dx= \int\limits{ arctg^{6}xd(arctgx)= \frac{ arctg^{7}x }{7}+C$