Question

Integrala de la 0 la pi/2 din cos2x.Cum o rezolv?

Answer 1

$\int\limits^ \frac{ \pi }{2} _0 {cos2x} \, dx= \frac{1}{2} \int\limits^ \frac{ \pi }{y} _0 {(2x)'cos2x} \, dx }= \frac{1}{2}sin2x$ de la 0 la π/2=1/2sinπ/2-1/2sin0=1/2.