Question

integrala de la 1 la 2 (4x+2)dx

Answer 1

Salut,

$\int_1^2(4x+2)dx=\left(4\cdot\dfrac{x^2}2+2x\right)\Bigg{|}_1^2=\left(4\cdot\dfrac{2^2}2+2\cdot 2\right)-\left(4\cdot\dfrac{1^2}2+2\cdot 1\right)=\\\\=12-4=8.$

Green eyes.