Question

integrala din x^4 / (x^2+1)

Answer 1

$\int\limits {\frac{x^4-1+1}{x^2+1} } \, dx =\int\limits {\frac{(x^2+1)(x^2-1)+1}{x^2+1} } \, dx =\int\limits {x^2-1} \, dx +\int\frac{1}{x^2+1} \ dx=\\\\=\frac{x^3}{3}-x+ arctgx+C$

Un alt exercitiu gasesti aici: https://brainly.ro/tema/956588

#SPJ9