Question

Intr-o gospodarie s-au crescut: gaini, rate si curci, in total -189 pasari. Ratele sunt cu 14 mai multe decat gainile, iar curcile sunt jumatate din mumarul gainilor.
 Cate pasari sunt de fiecare fel/
 Rezolvarea
I. Numarul partilor egale cu numarul mic:
Suma partilor egale:.........
Numarul gainilor:...............
Numarul ratelor:.......
raspuns :84 rate; 70 gaini; 35curci
rezolvatimio va rog

Answer 1

$g+r+c=189 \\\\ \boxed{r=g+14} \\\\\boxed{c= \frac{g}{2}} \\\\\\ g^{(2}+14^{(2}+\frac{g}{2}+g^{(2}=189^{(2} \\\\ 2g+28+g+2g=378 \\\\ 5g=378-28 \\\\ 5g=350 \ |:5 \\\\ \boxed{\boxed{g=70}} \\\\ r=70+14 \\\\ \boxed{\boxed{r=84}} \\\\ c= \frac{70}{2} \\\\ \boxed{\boxed{c=35}}$
 
                                                       OR
|.......|- nr. de gaini
|.......|.14.|-nr. de rate
|...| -nr. de curci

x-un segment

x+x+14+ x/2= 189
2x+x/2 =189-14

2x+x/2= 175   |*2 Inmultim toata relatia prin 2

4x+x=350

5x=350

x=350:5

x=70 -un segment ( nr gainilor)

70+14=84 -nr ratelor

70:2=35 -nr curcilor