Question

intr-o livada sunt 96 de pomi fructiferi.caisi,meri,peri,gutui.Cati pomi sunt de fiecare fel,daca 42 sunt caisi si meri,45 sunt peri si caisi si 39 sunt caisi si gutui?

Answer 1

m+c+p+g=96
c+m=42
p+c=45
c+g=39
3c+p+m+g=42+45+39=126
3c+96=126
3c=126-96=30
de unde nr.caisilor =30:2=15
de aici inlocuim in relatiile date:
p+15=45|-15
peri=30
15+m=42|-15
m=27
15+g=39|-15
gutui=24
v:15+30+27+24=96

Answer 2

a+b+c+d=96 a-caisi b-meri c-peri d-gutui a+b=42 a+c=45 a+d=39 42+c+d=96 c+d=96-42=54 45+b+d=96 b+d=96-45=51 39+b+c=96 b+c=96-39=57 a+b+a+c+b+c=42+45+57=144 2(a+b+c)=144 a+b+c=72 72+d=96 d=96-72=24 b+24=51 b=51-24=27 c+24=54 c=54-24 c=30 a+24=39 a=39-24=15