Question

Intr-o miscare uniform variata in timpul t=10s corpul parcurge distanta d=18m, viteza lui crescand de n ori.Care este acceleratia corpului?

Answer 1

$v=nv_0 \\ v^2=v_0^2+2ad \\ v=v_0+at \\ deci \\ at=v_0(n-1) \\ v_o=at/(n-1)$
inlocuieste in a doua ecuatie si scoti acceleratia
$a=2d/t^2(n+1)$