Question

Intr.un ∆ABC m(BAC)=90° AB=6 AC=8 BC=10. Aflati inaltimea ∆

Answer 1

$h_{(\Delta.dr.)}=\frac{AB\cdot{AC}}{BC}=\frac{6\cdot8}{10}=4,8$

Answer 2

h =AB*AC/BC =4*8 /10 =48/10 =4.8