Question

Intr-un calorimetru a carui capacitate calorica este C=150J/kg ,se afla o masa m1=250g apa cu caldura specifica c1=4185J/kgK la temperatura t1=15 grade celsius .Determinati temperaturaa de echilibru,daca in calorimetru se introduceun corp din sticla aflat la temperatura t2=85 grade celsius,de masa m2=150g si a carui calsura specifica este c2=800J/kgK.

Answer 1

Se da:
С=150J/kg
m1=250g=0,25kg
c1=4185J/kgK
t1=15C=288,15K
t2=85C=358,15K
m2=150g=0,15kg
c2=800+J/kgK
t=?K

Formule:
Q+Q1=-Q2
C*Δt1+c1*m1*Δt1=-c2*m2*Δt2
C*(t-t1)+c1*m1*(t-t1)=-c2*m2*(t-t2)
C*t-C*t1+c1*m1*t-c1*m1*t1=-c2*m2*t+c2*m2*t2
C*t+c1*m1*t+c2*m2*t=C*t1+c1*m1*t1+c2*m2*t2
t*(C+c1*m1+c2*m2)=C*t1+c1*m1*t1+c2*m2*t2
t=(C1*t1+c1*m1*t1+c2*m2*t2)/(C+c1*m1+c2*m2)

Calcule:
t=(150*288,15+4185*0,25*288,15+800*0,15*358,15)/(150+4185*0,25+800*0,15)=294,53K