Question

intr un cos era un numar de nuci. mama ia jumatate din cantitatea totala, tata ia o treime din rest iar copilul ia o patrime din noul rest.in cos raman 6 nuci. cate nuci au fost la inceput in cos?

Answer 1

x-x/2
m=x/2
t=1/3(x-x/2)=1/3(x/2)=x/6
c=1/4[x-x/2-1/3(x-x/2)]=1/4[x/2-x/6)]=1/4(x/3)=x/12
m+t+c+6=x
x/2+x/6+x/12+6=x
6x+2x+x+12*6=12x
72=12x-9x
72=3x
x=24  , 24 de nuci au fost la inceput in cos
verificare
m=12
t=(24-12):3=12:3=4
c=x/12=24/12=2
m=12,  t=4  si c=2
12+4+2+6=24
24=24
24=24