Question

intr-un depozit erau 1600t de cereale,orz cu 150 t mai mult ca ovaz,porumb de 6 ori mi mult ca ovazul,grau cu 50 de t mai mult ca porumbul. cate tone de cerele de fiecare fel sunt

Answer 1

1)150:50=3-t.ovaz. 2)1600×6=9600-t.porumb. 3)9600:3=3200-t orz.

Answer 2

orz + ovaz + p + g = 1600
orz = ovaz + 150
p = 6 ovaz
g = p + 50    =>  g = 6 ovaz + 50
ovaz + 150 + ovaz + 6 ovaz + 6 ovaz + 50 = 1600
14 ovaz = 1600 - 200
ovaz = 1400 : 14
ovaz = 100 tone
orz = 100 + 150
orz = 250 tone
p = 6 * 100
porumb = 600 tone
g = 6 * 100 + 50
grau = 650 tone
100 + 250 + 600 + 650 = 1600 t cereale