Question

Intr un oscilator liniar armonic avem
A=0.15m
niu=120 os/m
viteza=0.3pi m/s
Sa se afle fi.

Answer 1

ν= 120 os/min=2 Hz

ω=2πν=4π rad/s

v=ωA*cosωt<=>0,3π=4π*0,15*cos(4πt)<=>0,3=0,6cos(4πt)=>cos(4πt)=0,3/0,6=0,5=>4πt=arccos(0,5)<=>4πt=π/3=>t=1/12 s

φ=ωt=4π/12=π/3