Question

Intr-un rezervor se gasesc 268 t amestec echimolecular 2-propanol si 2-butanol.
Calculati: a)compozitia procentuala in % de greutate a amestecului de alcooli,
b)masa de alchene folosite pentru obtinerea alcoolilor​

Answer 1

Răspuns:

M,propanol=76kg/kmol

M,butanol= 88kg/kmol

DACA amestecul este format din 1 kmol propanol si 1kmol butanol;, m,amestec= 164kg

164kg amestec.........76kg propanol........88kg butanol

268000kg........................x.........................................y

x= 124195kg propanol

y=143805kg  butanol

x+y=268000kg

268000kg........124195kg...........143805kg

100kg................................x....................y

x=46,3% propanol

y=53,7% butanol

M,propena=42kg/kmol

M,butena= 56kg/kmol

CH2=CH-CH3 + HOH=====> CH3-CHOH-CH3

42kg....................................................76kg

x........                                         124195kg

x=68634kg 1 propena

CH2=CH-CH2-CH3+HOH---> CH3-CHOH-CH2-CH3

56KG.......................................................88KG

X..........................................................1438o5kg

x=91512kg 1 butena

verifica, te rog, calculele !!!

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