Question

Intr-un triunghi MNP dreptunghic in M se stie ca MN=6cm si MP=8cm . Calculati: NP ; sin P ; sin N ; cos P ; cos N ; tg P ; tg N ; ctg P ; ctg N.(Folositi metode de clasa a 7-a!)

Answer 1

NP²=MN²+MP²
NP²=6²+8²
NP²=36+64
NP=√100
NP=10

$sin = \frac{co}{ip }$
sin P
Co=MN
Ip=NP
sin P=MN/NP=6/10=3/5

sin N
Co=MP
Ip=NP
sin N=MP/NP=8/10=4/5

$cos = \frac{ca}{ip}$

cos P
Ca=MP
Ip=NP
cos P=MP/NP=8/10=4/5

Cos.N
Ca=MN
Ip=NP
cos.N=MN/NP=6/10=3/5

$tg = \frac{ co}{ca}$
Tg N
Co=MP
Ca=MN
Tg.N=MP/MN=8/6=4/3

Tg.P
Co=MN
Ca=MP
Tg.P=MN/MP=6/8=3/4

$ctg = \frac{ca}{co}$

Ctg P
Ca=MP
Co=MN
Ctg.P=MP/MN=4/3

Ctg.N
Ca=MN
Co=MP
Ctg.N=3/4
Sper că te am ajutat.